Turning Torso

taking the smaller of the two positive roots) t2 = 0.041 s = 41 ms, which implies that the total time spent in that bottom 15 cm (both ascending and descending) is 2(41 ms) = 82 ms. 65. The key idea here is that the speed of the head (and the torso as well) at any given time can be calculated by finding the area on the graph of the head’s acceleration versus time, as shown in Eq. 2-26: v1 − v0 = area between the acceleration curve and the time axis, from t0 to t1 (a) From Fig. 2.14a, we

taking the smaller of the two positive roots) t2 = 0.041 s = 41 ms, which implies that the total time spent in that bottom 15 cm (both ascending and descending) is 2(41 ms) = 82 ms. 65. The key idea here is that the speed of the head (and the torso as well) at any given time can be calculated by finding the area on the graph of the head’s acceleration versus time, as shown in Eq. 2-26: v1 − v0 = area between the acceleration curve and the time axis, from t0 to t1 (a) From Fig. 2.14a, we

taking the smaller of the two positive roots) t2 = 0.041 s = 41 ms, which implies that the total time spent in that bottom 15 cm (both ascending and descending) is 2(41 ms) = 82 ms. 65. The key idea here is that the speed of the head (and the torso as well) at any given time can be calculated by finding the area on the graph of the head’s acceleration versus time, as shown in Eq. 2-26: v1 − v0 = area between the acceleration curve and the time axis, from t0 to t1 (a) From Fig. 2.14a, we

taking the smaller of the two positive roots) t2 = 0.041 s = 41 ms, which implies that the total time spent in that bottom 15 cm (both ascending and descending) is 2(41 ms) = 82 ms. 65. The key idea here is that the speed of the head (and the torso as well) at any given time can be calculated by finding the area on the graph of the head’s acceleration versus time, as shown in Eq. 2-26: v1 − v0 = area between the acceleration curve and the time axis, from t0 to t1 (a) From Fig. 2.14a, we

taking the smaller of the two positive roots) t2 = 0.041 s = 41 ms, which implies that the total time spent in that bottom 15 cm (both ascending and descending) is 2(41 ms) = 82 ms. 65. The key idea here is that the speed of the head (and the torso as well) at any given time can be calculated by finding the area on the graph of the head’s acceleration versus time, as shown in Eq. 2-26: v1 − v0 = area between the acceleration curve and the time axis, from t0 to t1 (a) From Fig. 2.14a, we

taking the smaller of the two positive roots) t2 = 0.041 s = 41 ms, which implies that the total time spent in that bottom 15 cm (both ascending and descending) is 2(41 ms) = 82 ms. 65. The key idea here is that the speed of the head (and the torso as well) at any given time can be calculated by finding the area on the graph of the head’s acceleration versus time, as shown in Eq. 2-26: v1 − v0 = area between the acceleration curve and the time axis, from t0 to t1 (a) From Fig. 2.14a, we

taking the smaller of the two positive roots) t2 = 0.041 s = 41 ms, which implies that the total time spent in that bottom 15 cm (both ascending and descending) is 2(41 ms) = 82 ms. 65. The key idea here is that the speed of the head (and the torso as well) at any given time can be calculated by finding the area on the graph of the head’s acceleration versus time, as shown in Eq. 2-26: v1 − v0 = area between the acceleration curve and the time axis, from t0 to t1 (a) From…

taking the smaller of the two positive roots) t2 = 0.041 s = 41 ms, which implies that the total time spent in that bottom 15 cm (both ascending and descending) is 2(41 ms) = 82 ms. 65. The key idea here is that the speed of the head (and the torso as well) at any given time can be calculated by finding the area on the graph of the head’s acceleration versus time, as shown in Eq. 2-26: v1 − v0 = area between the acceleration curve and the time axis, from t0 to t1 (a) From…

address my prayers to The Universe, The Great Void, The Force, The Supreme Self, The Whole, The Creator, The Light, The Higher Power, or even the most poetic manifestation of God’s name, taken, I believe, from the Gnostic gospels: “The Shadow of the Turning.” I have nothing against any of these terms. I feel they are all equal because they are all equally adequate and inadequate descriptions of the indescribable. But we each do need a functional name for this indescribability, and “God”…

bare torso because he thought he had a damn good build. He did, too. I have to admit it. 4 I didn't have anything special to do, so I went down to the can and chewed the rag with him while he was shaving. We were the only ones in the can, because everybody was still down at the game. It was hot as hell and the windows were all steamy. There were about ten washbowls, all right against the wall. Stradlater had the middle one. I sat down on the one right next to him and started…