Estatica Dos Fluidos

Estática dos Fluidos
Ex 1

P1*A1 + Pa(A4-A2) = P4*A4 + Pa(A1-A2)
20*25 + Pa(30-5) = P4*30 + Pa(25-5)
450 + 25Pa = 30P4+ 20Pa
30P4 = 450 + 25Pa – 20Pa
30P4 = 450 + 5Pa (eq. 1)

F + K*x = Pa*A3
2500 + 170*3 = Pa*50
50Pa = 3010
Pa = 3010/50
Pa = 60,2 N/cm²

Na eq. 1
30*P4 = 450 + 5*60,2
30P4 = 450 + 301
P4 = 751/30
P4 = 25,03 N/cm²

No S.I.
1 m² = 10000 cm²
P4 = 250300 N/m²

Ex 2

P1*A1 + Pa(A4-A2) = P4*A4 + Pa(A1-A2)
20*30 + Pa(30-5) = P4*30 + Pa(30-5)
600 + 25Pa = 30P4+ 25Pa
30P4 = 600 + 25Pa – 25Pa
30P4 = 600 + 0Pa
P4 = 600/30
P4 = 20 N/cm²

1 m² = 10000 cm²

P4 = 10000*20 N/m²
P4 = 200000 N/m²

1 Pa = 1 N/m²
1 KPa = 0,001 N/m²

P4 = 200000*0,001 kPa
P4 = 200 kPa

Ex 3

ΣMo = 0
F1*0,2 + Fa*0,1 = 0
200.0,2 + Fa*0,1 = 0
0,1Fa = -40
Fa = -40/0,1
Fa = -400 N

Pa = Pb
Fa/Aa = Fb/Ab
400/(π*0,05²/4) = Fb/(π*0,25²/4)
203718,32 = Fb/0,049
Fb = 203718,32*0,049
Fb = 10000 N

Ex 4

Pa = Pb
Fa/Aa = Fb/Ab
800/(π*0,03²/4) = Fb/(π*0,45²/4)
1131768,484 = Fb/0,159
Fb = 1131768,484*0,159
Fb = 180000 N
Fb = 180 kN

Ex 5

Pa = Pb
Fa/Aa = Fb/Ab
500/(π*0,03²/4) = Fb/(π*0,45²/4)
707355,3026 = Fb/0,159
Fb = 707355,3026 *0,159
Fb = 112500 N

ΣMo = 0
Fa*0,15 + Fb*x = 0
500.0,15 + 112500*x = 0
75 = -112500*x x = -75/112500 x = -0,000667 m x = -0,0667 cm