Universitarios

Resultado
Tabela 1 – Diâmetro do Cano PVC
Diâmetro 1 =31,20
Diâmetro 2 = 31,00
Diâmetro 3 = 31,30
Diâmetro 4 = 33,25
Diâmetro 5 = 33,30
Diâmetro 6 = 33,55
Diâmetro 7 = 33,50
Diâmetro 8 = 33,30
Diâmetro 9 = 33,40

ẋ=i=1nxin s=i=1n(xi-ẋ)²n-1 Portanto : Portanto : ẋ= Média S= Desvio Padrão i=1nxi = soma de x+i n=Numero de medidas

ẋ= 31,20+31,OO+31,30+33,25+33,30+33,55+33,50+33,30+33,409 x=32,64 mm s=31,20-32,64231,00-32,64231,30-32,64233,25-32,64233,30-32,6433,55-32,64233,50-32,64233,30-32,64233,40-32,64229-1 s=31,20-32,64231,00-32,64231,30-32,64233,25-32,64233,30-32,64233,55-32,6433,50-32,64233,30-32,6433,40-32,642228 s=2,07+2,69+1,80+0,37+0,44+o,83+0,74+0,44+0,588 S= 1,245 mm

Área da secção transversal
A=πr2

A=3,14 .1,245²
A= 3,14.1,55
A = 4,867
Tabela 2 – CD
Diâmetro Interno
1 =15 mm
2 = 15 mm
3 = 15 mm
4 = 15,20 mm
5 =15,10 mm
6 = 15,35 mm
7 = 15 mm
8 =15,40 mm
9 = 15,30 mm

ẋ= 15,00+15,00+15,00+15,20+15,10+15,35+15,00+15,40+15,309
X= 15,15 s=15,00-15,15215,00-15,15215,00-15,15215,20-15,1515,10-15,15 15,35-15,1515,00-15,1515,40-15,1515,30-15,152222229-1 s=0,0225+0,0225+0,0225+0,0025+0,0025+0,04+0,0225+0,0625+0,02258 logo : S=0,0275mm

Diâmetro Externo
1=120,00
2=119,85
3=119,60
4=120,00
5=118,90
6=120,00
7=121,25
8=120,40
9=120,05
ẋ= 120,00+119,85+119,60+120,00+118,90+120,0+121,25+120,40+120,059
X = 120,00 mm
= 15,15 s=120,00-120,002119,85-120,002119,60-120,002120,00-120,002118,90-120,002120,00-120,002121,25-120,002120,40-120,002120,05-120,0029-1 s=0+0,0225+0,16+0+1,21+0+1,56+0,16+0,00258
S=0,38