Atividade

01º)
180----∏
x-------2/∏

x∏=180.2/∏=360/∏

x=360/∏. 1/∏

x=36°31´

02º)
360/6=6
30/6=5°
150°-5°=145° no relógio os graus são 150 menos 5 ° fica 145°.
03º) H=h+x
H=1,70+a tg

04º)tgB= h/x

X=h /tgB

TG=h/d+x

H=d.tg+x.tg

h/dtgB=h-d.tg /

h+tgB-htg=d.tg. tgB

x=360/∏/∏

x=360/9.85

h-tg

x=d.tg/tg

h.tg=h.tgB-d.tg=-d.tg.tgB.(-1)

H.(tgB-tg )=dtgtgB

h=d.tg2tgB/tgB-tg

05º) a.sen=420°

429/360

360
(60) sen60°=

b.Sen=750°

750/360=2

720

(30) sen30°=1/2

06º)
a.1630/360=4

( 190) °=190 °

b.23000/360=9

(140)=°=140°

c.-1430/360=-3

(350)=360-350=1°.

07º)
a.780/360=2

720

(60)

Cos60°=1/2

b.1200/360=3

1080

120°

Cos120°=-1/2

08º)=1

x=1-4.6/25

Cox=

Cox=±1/5

Secx=1/cosx

Sexc=1/-1/5=-5

09º)senx=-7/25 e ∏<x<3∏/2

Y=tgx-cosx/(1+cosx)(1-cosx)

Y=senx/ós.cosx/(1+cosx)(1-cosx)

Y=senx/(1+cosx)(1-cosx)

Y=senx/(1-24/25)(1+24/25)

Y=-7/25/(25/24/25)(25+24/25)

Y=-7/25/1/25.49/25

1-24/25

25-24/25

Y=-7/25.625/49

Y=-25/7

10º)

y = cossec α – sen α sen α – cos α

y = 1 - sen α sen α sen α – cos α

y = 1 – sen2 α sen α sen α – cos α

y = cos2 α sen α sen α – cos α

2 5 2 5 5 5

y = 5 - 2 5 5 5

Y = 4 5 5 - 5 5 y = 20 . – 5 5 5

y = - 100 5

y = - 20

tg α = sen α cos α

1 = sen α
2 cos α

Cos α = 2 sen α

Cos α = 2 . 5 5

sen2 α + cos α = 1 sen2 α + ( 2 sen2 α) = 1 sen2 α + 4 sen2 α = 1
5 sen2 α = 1 sen2 α = 1 5

sen α = ± 1 5

sen α = 1 5 5 5

sen α = 5