fisica

Exercícios

1.
Vf=Vp(1+ i)n
Vf=10000.(1+ 0,012)18
Vf=12.395,08

2.

Vf=Vp(1+ i)n
20.000,00=Vp.(1+0,12)4
VP= 12.710,36

3.
Vf=Vp(1+ i)n
11200=10000(1+i)12
(1+i)12= 11200 10000 i = 0,00949 i = 0,949%

4.
Vf=Vp(1+ i)n
Vf=10000(1+0,012)24
Vf=13.314,72

5.
Vf=Vp(1+ i)n
3Vp=Vp(1+0.01)t
T=110,4096 meses

6.
J=C.I.T

J=100000.0,015.3
J=4.500
100000*20%=80.000,00
Valor líquido= 80.000-4.500
Valor líquido = 75.500,00
Taxas
J=C.I.T
4.500=75500.i.3
i=0,019875 i= 1,98 % ao mês

Vf=Vp(1+ i)n
80.000=75500(1+i)3
i = 0,019485 i = 1,9485% ao mês

7.

Vf1=Vp1(1+ i)n
10000= Vp1(1+0.015)6
Vp1=9.145,4219

Vf2=Vp2(1+ i)n
20000= Vp2(1+0.015)12
Vp2=16.727,7484

Vp= Vp1+Vp2
Vp= 25.873,17 8.

Vf1=Vp1(1+ i)n
10000= Vp1(1+0.01)3
Vp1=10.364,33728
Vf2=Vp2(1+ i)n
50.000= Vp2(1+0.012)5
Vp2=47.071,14
Vp= Vp1+Vp2
Vp=57.435,47
9.

i = 1,2% a.m. = (1,012)6 - 1 = 0,074194873 a.s.

100000/(1ⓜ┤+ⓜ0.074194873)^1 +100000/(1ⓜ┤+ⓜ0.074194873)^2 =197755.02/(1ⓜ┤+ⓜ0.074194873)^t

t=log_(1000000000/1074194873) (1152330485000000000000000/1267713637112565461278431)

t=1,133333367287 trimestres

t = 1,33333367287 . 6 = 8 meses

10.

Vf=Vp(1+ i)n
106.152,02=Vp(1+0.01)6
Vp=100.000,004
Vf=Vp(1+ i)n
90.000=Vp(1+0.01)6
Vp=84.784,07

Valor a ser abatido= 100.000,004 – 84.784,07 =15.215,93

11.

Vf=Vp(1+ i)n
10000=Vp(1+0,015)0,7
Vp= 9.896,32
12.
Vf=Vp(1+ i)n
Vf=10000(1+0.0125)0,6
Vf=10.074,81

13.

Vf=Vp(1+ i)n
Vf=50.000(1+0.015)3
Vf=52.283,92

Vf=Vp(1+ i)n
Vf=100.000(1+0.01)3
Vf=103.030.10 Letra B, porque o lucro será maior.

14.
(1ⓜ┤+ⓜ0.12)^(1/2)/(1ⓜ┤+ⓜ0.08)^(1/2) -1=i/(1-i)
0,018350154 x (1 - i) = i
0,018350154 - 0,018350154i = i
0,018350154 = 1,018350154i i = 0,018350154/1,018350154 i = 0,01802 = 1,802%
01. A massa específica de um combustível leve é 805 kg/m
3
. Determinar o peso específico e a densidade relativa