Trabalho de eletrica
Trabalho de elétrica – Situação de Aprendizagem
Professor :
Aluno: Marcos Antonio Maciel
Blumenau; 24 de Outubro de 2014.
Ra= R5+R6+R7=10+10+10=30Ώ
Rb= Ra.R8 = 15.30 = 450 =10 Ώ Ra.R8 15+30 45
Rc =Rb+R4 = 10+10 = 20 Ώ
Rd = Rc.R9 = 20.30 = 600 = 12 Ώ Rc+R9 20+30 50
Re = Rd+R3 = 32+20 = 32 Ώ
Rf= Re.R2 = 32.12 = 384 = 8,73 Ώ
Rg= Rf+R1 = 8,73+10 = 18,73 Ώ RT = 18,73 Ώ I = V = 12 = 0,64A R 18,73
Ra = R14.R13 = 40.20 = 800 = 13,33 Ώ R14+R13 40+20 60
Rb = Ra . R12 = 13,33.12 = 159,96 = 6,31 Ώ Ra + R12 13,33+12 25,33
Rc =Rb+R11+R10 = 56,31 Ώ
RT = 56,31 Ώ
I = V = 20 = 0,35A R 56,31
Ra = R18.R19 = 40.12 = 480 = 9,23 Ώ R18+R19 40+12 52
Rb = Ra.R20 = 9,23. 12 = 110,76 = 5,22 Ώ Ra+R20 9,23+12 21,23
Rc = Rb+R21+R17 = 5,22+20+40 = 65,22 Ώ
Rb = R15+R16 = 20 Ώ
Re = Rc.Rd = 65,22.20 = 1304,4 = 15,31 Ώ Rc+Rd 65,22+20 85,22
RT = 15,31 Ώ
I = V = 7 = 0,46A R 15,31
Ra = R26 E R27 12 = 6 Ώ 2
Rb = R23.R25 = 20.10 = 200 = 6,66 Ώ R23+R25 20+10 30
Rc = Rb+ R24 = 6,66+ 10 = 16,66 Ώ
Rd = Ra +R22 = 46 Ώ
Re = Rd.Rc = 46.16,66 = 766,36 = 12,23 Ώ Rd+Rc 46+16,66 62,66
RT = 12,23 Ώ
I = V = 36