Agronomia

ANÁLISE TEXTURAL
LATOSSOLO VERMELHO-AMARELO
Alunos: DANIELLE RIBAS, FERNANDO SABADIN, MARIA APARECIDA,
NATÁLIA PATRÍCIA e PAULO MONTEIRO
3- Resultados
% Argila H2O Hor.A
50,007-------7,32
1000g----------x
X= 146,3g/Kg
X= 14,63%
% Silte H2O Hor. A
50,007------5,64
1000g--------x
X= 112,7 g/Kg
X=11,27%
% Areia H2O Hor. A
1000-(146,3 + 112,7)=
= 741g/Kg
= 74,1%
% Argila H2O Hor.B
50,082-------9
1000g-------x
X=179,7g/Kg
X=17,97%
% Silte H2O Hor.B
50,082-------23
1000g--------x
X=459,2g/Kg
X=45,92%
% Areia H2O Hor.B
X=1000g-(179,7+459,2)=
=361,1g/Kg
=36,11%

Índice de Floculação
Hor. A NaOH e H2O
IF= [(559,9 – 146,3)/559,9]x100
IF= 73,87%

Hor. B
IF= [(519,1 – 179,7)/519,1]x100
IF=65,38%

TFSE
A= 50,007
B= 50,082

TFSA
A= 6,633
B= 1,339

A= 77,666 – 27,659 = 50,007
A= 50,007 – 43,374 = 6,633

50,007-----6,633
100 -------- X
X= 13,26%

% Argila NaOH Hor. A
50,007 ------28
1000g--------x
X=559,9g/Kg
X=55,99%

% Silte NaOH Hor. A
50,007-------5,64
1000g-------x
X=112,78g/Kg
X=11,27%
% Areia NaOH Hor. A
1000-(559,9 + 112,78)=
= 327,32g/Kg
= 32,78%
% Argila NaOH Hor. B
50,082------26
1000g-------x
X=519,1g/Kg
X=51,91%
% Silte NaOH Hor. B
50,082------8
1000g-------x
X=159,7g/Kg
X=15,97%
% Areia NaOH Hor. B
1000-(519,1+159,7)=
= 321,2g/Kg
=32,12%

Umidade total do solo:

Horizonte A Horizonte B
50,007g-------21,07 50,082--------20,024
100-----------U 100-----------U
U=42,13% U=89,98%

Densidade do solo Ms/v

Ds = 48,290 = 0,48 g/cm³ Horizonte A 100 Ds = 48,743 = 0,48 g/cm³ Horizonte B 100

Densidade de partícula do solo
V= 50-42 =