Marsha

and the difference between that distance and 100 m: 100 m − 87 m = 13.0 m (b) Using the definition of average speed, find the time required by John to complete the 100-m run: tJohn = distance run 100 m = = 16.7 s John' s speed 6 m s Marsha wins by 16.7 s – 14.5 s = 2.2 s Alternatively, the time required by John to travel the last 13.0 m is (13 m)/(6 m/s) = 2.17 s 57 • Picture the Problem The average velocity in a time interval is defined as the displacement divided by the…

and the difference between that distance and 100 m: 100 m − 87 m = 13.0 m (b) Using the definition of average speed, find the time required by John to complete the 100-m run: tJohn = distance run 100 m = = 16.7 s John' s speed 6 m s Marsha wins by 16.7 s – 14.5 s = 2.2 s Alternatively, the time required by John to travel the last 13.0 m is (13 m)/(6 m/s) = 2.17 s 57 • Picture the Problem The average velocity in a time interval is defined as the displacement divided by the…

and the difference between that distance and 100 m: 100 m − 87 m = 13.0 m (b) Using the definition of average speed, find the time required by John to complete the 100-m run: tJohn = distance run 100 m = = 16.7 s John' s speed 6 m s Marsha wins by 16.7 s – 14.5 s = 2.2 s Alternatively, the time required by John to travel the last 13.0 m is (13 m)/(6 m/s) = 2.17 s 57 • Picture the Problem The average velocity in a time interval is defined as the displacement divided by the…

that distance and 100 m: and Marcia wins by (b) Using the definition of average speed, find the time required by John to complete the 100-m run: tJohn = 100 m − 87 m = 13.0 m distance run 100 m = = 16.7 s John' s speed 6 m s Marsha wins by 16.7 s – 14.5 s = 2.2 s Alternatively, the time required by John to travel the last 13.0 m is (13 m)/(6 m/s) = 2.17 s 57 • Picture the Problem The average velocity in a time interval is defined as the displacement divided…

and the difference between that distance and 100 m: 100 m − 87 m = 13.0 m (b) Using the definition of average speed, find the time required by John to complete the 100-m run: tJohn = distance run 100 m = = 16.7 s John' s speed 6 m s Marsha wins by 16.7 s – 14.5 s = 2.2 s Alternatively, the time required by John to travel the last 13.0 m is (13 m)/(6 m/s) = 2.17 s 57 • Picture the Problem The average velocity in a time interval is defined as the displacement divided by the…

and the difference between that distance and 100 m: 100 m − 87 m = 13.0 m (b) Using the definition of average speed, find the time required by John to complete the 100-m run: tJohn = distance run 100 m = = 16.7 s John' s speed 6 m s Marsha wins by 16.7 s – 14.5 s = 2.2 s Alternatively, the time required by John to travel the last 13.0 m is (13 m)/(6 m/s) = 2.17 s 57 • Picture the Problem The average velocity in a time interval is defined as the displacement divided by the…

faiths in signing the URI charter and forming a URI Cooperation Circle in 2000. (Bahai News, “Interfaith Group Aims To End Violence, http://bahai-library.org/newspapers/100300.html, printed 1/11/03). 8. Unity of Salt Lake, “The Staff,” biography of Marsha Pilgeram, board president, who says, “my heart is with URI and Unity,” http://www.unityslc.org/staff_board.html, printed 2/11/03. 9. Universal Oneness United (“Mission Statement,” http://www.uou.to/mission.htm, printed 1/11/03),…

Timothy Smaby Michael F. Spivey Vic Stanton Charlene Sullivan George S. Swales, Jr. Philip Swensen Philip Swicegood John G. Thatcher Harry Thiewes A. Frank Thompson Joseph Trefzger Michael R. Vetsuypens Joe Walker Jun Wang James Washam Alan Weatherford Marsha Weber Jill Wetmore Mark White Annie Wong David J. Wright Steve B. Wyatt Tung-Hsiao Yang Morris Yarmish Michael Young Mei Zhang J. Kenton Zumwalt Tom Zwirlein Vários dos mais respeitados colegas contribuíram com ensaios originais…