Trabalho Ava Pronto 1
CALCULO I atividade avaliativa
Caxias do Sul
2014/1
Exemplo1.1.5
a).
R(x)= x.(-0,27x + 51)
L(x)= x.(-0,27x + 51) – (2,23x² +3,5x +85)
b).
L(x)= x.(-0,27x + 51) – (2,23x² +3,5x +85)
L(x)= -0,27x² + 51x – 2,23x² -3,5x -85
L(x)= -2,5x² + 47,5x -85 x´= 2 x´´= 17
Exemplo 1.1.6
a).
C(n)= n³-30n²+500n+200
C(10)= 10³-30.10² +500.10 +200
C(10) =1000 – 3000 +5000+200
C(10) = 3200
b).
C(n)= n³-30n²+500n+200
C(9)= 9³-30.9² +500.9 +200
C(9) = 729-2430+4500+200
C(9) = 2999
C(10)-C(9)=3200-2999=201
Exemplo 1.1.11
a).
C(p(t))= 0,5.(10+0,1t²) +1
C(p(t))= 5 + 0,05t² +1
C(p(t))= 0,05t² +6
b).
6,8 = 0,05t² + 6
6,8 - 6 = 0,05t²
0,8 = 0,05t²
0,8 / 0,05 = t²
16 = t² = t t = 4
64.
F(x)= -x³+6x²+15x
a).
f(2)=-2³+6.2²+15.2 f(2)= -8+24+30 f(2) = 46
b). f(1) = -1+6 +15 f(1) = 20
46-20= 26
70.
a).
H(t) = -4,9t² + 80
H(3)= -4,9.3² + 80
H(3)= -44,1+80
H(3) = 35,9 m
b). x = H(0) – H(3) x = 80 – 35,9 x = 44,1
c).
85 m
d).
H(t) = 0
-4,9t² +80 = 0
-4,9t² = 80 t² = 80/4,9 t² = 16,32 t = t = 4,04
1.
2.
3.
a).
L(x)= 10x – (x³/3 -2x² -10x + 10)
b).
L(x)= -x²+4x
c).
L(x)= -x² + 4x +0
-4± √4²-4.-1.0 -2
-4±4 = 0 -2 4
4.
V(t) = 8t –t²
a). v(1)=8.1-1² v(1)= 7 v(2) =8.2-2² v(2)= 12 v(média) = 9.5m/s
b). v(3)= 8.3 -3² v(3)= 15m/s
c).a(t) 8 – 2t a(0) 8-2.0 = 8 a(1) 8-2.1 = 6 a(2) 8-2.2 = 4 a(3) 8-2.3 = 2 a(media)= 5m/s²
d). a(5) 8 – 2.5 = -2m/s²