ANA REDES
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2 páginas
PRONATEC - CURSO TÉCNICO EM INFORMÁTICA – TURMA: A TURNO: NOITE Disciplina: REDES DE COMPUTADORES
Professor: ALESSANDRO FAZENDA Data: 13 / 04 / 2015
Nome: ANA PAULA BOENO
1.A rede 23.0.0.0/8 deve ser divida em sub-redes com 12 bits de máscara de rede. Liste os endereços de rede e de broadcast das sub-redes criadas.
23.0000|0000.00000000.00000000 = 23.0.0.0
23.0000|1111.11111111.11111111 = 23.15.255.255 – Broadcast
23.0001|0000.00000000.00000000 = 23.16.0.0
23.0001|1111.11111111.11111111 = 23.31.255.255 – Broadcast
23.0010|0000.00000000.00000000 = 23.32.0.0
23.0010|1111.11111111.11111111 = 23.47.255.255 – Broadcast
23.0011|0000.00000000.00000000 = 23.48.0.0
23.0011|1111.11111111.11111111 = 23.63.255.255 – Broadcast
23.0100|0000.00000000.00000000 = 23.64.0.0
23.0100|1111.11111111.11111111 = 23.79.255.255 – Broadcast
23.0101|0000.00000000.00000000 = 23.80.0.0
23.0101|1111.11111111.11111111 = 23.95.255.255 – Broadcast
23.0110|0000.00000000.00000000 = 23.96.0.0
23.0110|1111.11111111.11111111 = 23.111.255.255 – Broadcast
23.0111|0000.00000000.00000000 = 23.112.0.0
23.0111|1111.11111111.11111111 = 23.127.255.255 – Broadcast
23.1000|0000.00000000.00000000 = 23.128.0.0
23.1000|1111.11111111.11111111 = 23.143.255.255 – Broadcast
23.1001|0000.00000000.00000000 = 23.144.0.0
23.1001|1111.11111111.11111111 = 23.159.255.255 – Broadcast
23.1010|0000.00000000.00000000 = 23.160.0.0
23.1010|1111.11111111.11111111 = 23.175.255.255 - Broadcast
23.1011|0000.00000000.00000000 = 23.176.0.0
23.1011|1111.11111111.11111111 = 23.191.255.255 - Broadcast
23.1100|0000.00000000.00000000 = 23.192.0.0
23.1100|1111.11111111.11111111 = 23.207.255.255 - Broadcast
23.1101|0000.00000000.00000000 = 23.208.0.0
23.1101|1111.11111111.11111111 = 23.223.255.255 - Broadcast
23.1111|0000.00000000.00000000 = 23.240.0.0
23.1111|1111.11111111.11111111 = 23.224.255.255 - Broadcast
2. A rede 200.230.50.0/24 deve ser divida em 8 novas sub-redes. Calcule o número de bits da máscara de rede