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1:18 PM Page 316 316 Chapter 5 Distributed Forces Sample Problem 5/18 A rectangular plate, shown in vertical section AB, is 4 m high and 6 m wide (normal to the plane of the paper) and blocks the end of a fresh-water channel 3 m deep. The plate is hinged about a horizontal axis along its upper edge through A and is restrained from opening by the fixed ridge B which bears horizontally against the lower edge of the plate. Find the force B exerted on the plate by the ridge.…

equal to 1.0 μm is 1.0 × 10−4. (c) Since 1 yd = (3 ft)(0.3048 m/ft) = 0.9144 m, 1.0 yd = ( 0.91m ) 106 μ m m = 9.1 × 105 μ m. ( )( ) ( )( ) ( ) 2. (a) Using the conversion factors 1 inch = 2.54 cm exactly and 6 picas = 1 inch, we obtain 1 inch 6 picas ≈ 1.9 picas. 0.80 cm = ( 0.80 cm ) 2.54 cm 1 inch (b) With 12 points = 1 pica, we have 0.80 cm = ( 0.80 cm ) 1 inch 2.54 cm 6 picas 1 inch 12 points ≈ 23 points. 1 pica 3. Using the given conversion…

the Concept The fundamental physical quantities in the SI system include mass, length, and time. Force, being the product of mass and acceleration, is not a fundamental quantity. (c) is correct. 2 • Picture the Problem We can express and simplify the ratio of m/s to m/s2 to determine the final units. Express and simplify the ratio of m/s to m/s2: m 2 s = m ⋅ s = s and (d ) is correct. m m ⋅s 2 s 3 • Determine the Concept Consulting Table 1-1 we note that the prefix giga means 109.…

equal to 1.0 μm is 1.0 × 10−4. (c) Since 1 yd = (3 ft)(0.3048 m/ft) = 0.9144 m, 1.0 yd = ( 0.91m ) 106 μ m m = 9.1 × 105 μ m. ( )( ) ( )( ) ( ) 2. (a) Using the conversion factors 1 inch = 2.54 cm exactly and 6 picas = 1 inch, we obtain 1 inch 6 picas ≈ 1.9 picas. 0.80 cm = ( 0.80 cm ) 2.54 cm 1 inch (b) With 12 points = 1 pica, we have 0.80 cm = ( 0.80 cm ) 1 inch 2.54 cm 6 picas 1 inch 12 points ≈ 23 points. 1 pica 3. Using the given conversion…

. . . . . . . . . . . . . . . . . . . . . 2 Instalação Desktop Debian e CentOS 7 2.1 Instalação do Debian . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 8 2.1.1 Instalação CentOS: . . . . . . . . . . . . . . . . . . . . . . . . . 16 3 Primeiros Passos 30 3.1 Introdução teórica . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 31 3.2 Terminal Virtual . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 33 3.3 Logon . . . . . . . . . . . . . . . . . . . . . .

equal to 1.0 μm is 1.0 × 10−4. (c) Since 1 yd = (3 ft)(0.3048 m/ft) = 0.9144 m, 1.0 yd = ( 0.91m ) 106 μ m m = 9.1 × 105 μ m. ( )( ) ( )( ) ( ) 2. (a) Using the conversion factors 1 inch = 2.54 cm exactly and 6 picas = 1 inch, we obtain 1 inch 6 picas 0.80 cm = ( 0.80 cm ) ≈ 1.9 picas. 2.54 cm 1 inch (b) With 12 points = 1 pica, we have 0.80 cm = ( 0.80 cm ) 1 inch 2.54 cm 6 picas 1 inch 12 points ≈ 23 points. 1 pica 3. Using the given conversion…

equal to 1.0 μm is 1.0 × 10−4. (c) Since 1 yd = (3 ft)(0.3048 m/ft) = 0.9144 m, 1.0 yd = ( 0.91m ) 106 μ m m = 9.1 × 105 μ m. ( )( ) ( )( ) ( ) 2. (a) Using the conversion factors 1 inch = 2.54 cm exactly and 6 picas = 1 inch, we obtain 1 inch 6 picas 0.80 cm = ( 0.80 cm ) ≈ 1.9 picas. 2.54 cm 1 inch (b) With 12 points = 1 pica, we have 0.80 cm = ( 0.80 cm ) 1 inch 2.54 cm 6 picas 1 inch 12 points ≈ 23 points. 1 pica 3. Using the given conversion…

equal to 1.0 μm is 1.0 × 10−4. (c) Since 1 yd = (3 ft)(0.3048 m/ft) = 0.9144 m, 1.0 yd = ( 0.91m ) 106 μ m m = 9.1 × 105 μ m. ( )( ) ( )( ) ( ) 2. (a) Using the conversion factors 1 inch = 2.54 cm exactly and 6 picas = 1 inch, we obtain 1 inch 6 picas 0.80 cm = ( 0.80 cm ) ≈ 1.9 picas. 2.54 cm 1 inch (b) With 12 points = 1 pica, we have 0.80 cm = ( 0.80 cm ) 1 inch 2.54 cm 6 picas 1 inch 12 points ≈ 23 points. 1 pica 3. Using the given conversion…

equal to 1.0 μm is 1.0 × 10−4. (c) Since 1 yd = (3 ft)(0.3048 m/ft) = 0.9144 m, 1.0 yd = ( 0.91m ) 106 μ m m = 9.1 × 105 μ m. ( )( ) ( )( ) ( ) 2. (a) Using the conversion factors 1 inch = 2.54 cm exactly and 6 picas = 1 inch, we obtain 1 inch 6 picas 0.80 cm = ( 0.80 cm ) ≈ 1.9 picas. 2.54 cm 1 inch (b) With 12 points = 1 pica, we have 0.80 cm = ( 0.80 cm ) 1 inch 2.54 cm 6 picas 1 inch 12 points ≈ 23 points. 1 pica 3. Using the given conversion…

of the force P required to maintain equilibrium. SOLUTION FBD CD: ΣM C = 0: (12 ft ) Dy − ( 9 ft ) Dx = 0 3Dx = 4 Dy (1) ΣM B = 0: ( 30 ft ) D y − (15 ft ) Dx − (18 ft )( 50 lb ) = 0 FBD BCD: Solving (1) and (2) 2D y − Dx = 60 lb D x = 120 lb D y = 90 lb (2) FBD Cable: ΣM A = 0: ( 42 ft )( 90 lb ) − ( 30 ft )( 50 lb ) − (12 ft )(150 lb ) − (15 ft ) P = 0 P = 32.0 lb PROBLEM 7.99 Knowing that WB = 40 lb and WC = 22 lb, determine the magnitude of the…