Atps4 estatistica
1260 palavras
6 páginas
Colunas1 x - x (x - x)² Média : 507,3500/100= 5,0735Amostras-> x Moda: 510
510 510 - 5,0735 = 504,9265 (504,9265)² = 254.950,7704 Mediana: 507,5000
510 510 - 5,0735 = 504,9265 (504,9265)² = 254.950,7704
510 510 - 5,0735 = 504,9265 (504,9265)² = 254.950,7704
505 505 - 5,0735 = 499,9265 (499,9265)² =249.926,5054 Variância Amostral
505 505 - 5,0735 = 499,9265 (499,9265)² =249.926,5054 S² = ∑(x - x)² = (25.228.940,98)/100-1
510 510 - 5,0735 = 504,9265 (504,9265)² = 254.950,7704 n-1
510 510 - 5,0735 = 504,9265 (504,9265)² = 254.950,7704 S²= (25.228.940,98)/99 = 254.837,7877
505 505 - 5,0735 = 499,9265 (499,9265)² =249.926,5054
500 500- 5,0735 = 494,9265 (494,9265)² = 244.952,2404 Desvio Padrão Amostral
515 515 - 5,0735 = 509,9265 (509,9265)² =260.025,0354 S=√S²
505 505 - 5,0735 = 499,9265 (499,9265)² =249.926,5054 S=√254.837,7877
510 510 - 5,0735 = 504,9265 (504,9265)² = 254.950,7704 S= 504,8146
505 505 - 5,0735 = 499,9265 (499,9265)² =249.926,5054
505 505 - 5,0735 = 499,9265 (499,9265)² =249.926,5054
510 510 - 5,0735 = 504,9265 (504,9265)² = 254.950,7704
510 510 - 5,0735 = 504,9265 (504,9265)² = 254.950,7704
505 505 - 5,0735 = 499,9265 (499,9265)² =249.926,5054
505 505 - 5,0735 = 499,9265 (499,9265)² =249.926,5054
515 515 - 507,3500 = 7,6500 (509.9265)² = 260.025,0354
505 505 - 5,0735 = 499,9265 (499,9265)² =249.926,5054
510 510 - 5,0735 = 504,9265 (504,9265)² = 254.950,7704
505 505 - 5,0735 = 499,9265 (499,9265)² =249.926,5054
505 505 - 5,0735 = 499,9265 (499,9265)² =249.926,5054
505 505 - 5,0735 = 499,9265 (499,9265)² =249.926,5054
505 505 - 5,0735 = 499,9265 (499,9265)² =249.926,5054
510 510 - 5,0735 = 504,9265 (504,9265)² = 254.950,7704
510 510 - 5,0735 = 504,9265 (504,9265)² = 254.950,7704
505 505 - 5,0735 = 499,9265 (499,9265)² =249.926,5054
505 505 - 5,0735 = 499,9265 (499,9265)² =249.926,5054
505 505 - 5,0735 = 499,9265