Stop Motion

Cap 6 1. We do not consider the possibility that the bureau might tip, and treat this as a purely horizontal motion problem (with the person’s push F in the +x direction). Applying Newton’s second law to the x and y axes, we obtain , max 0 s N F f ma F mg − − respectively. The second equation yields the normal force FN = mg, whereupon the maximum static friction is found to be (from Eq. 6-1) fs,max s mg . Thus, the first equation becomes F mg ma s −0…

Roundabouts ...........................25 -v- Know What Is Ahead .............. 46 Know What Is at Your Side ..... 48 Know What Is Behind You ...... 48 Clean Windows and Mirrors ... 49 Adjust Seat and Mirrors.......... 49 How Well Can You Stop?........ 49 Driving in the Fog ....................... 50 Driving in Darkness .................... 50 Driving in Rain or Snow ...............51 Driving in Hill Country or Curves .51 Horn, Headlights, and Emergency Signals…

Já no cinema a tecnologia está sendo usada para criar moldes e protótipos de personagens, modelos em escala de objetos, carros e ambientes para produção de cenas de alta periculosidade e até mesmo personagens inteiros para produção de filmes em stop-motion. Nesta área a integração das peças tridimensionais com a modelagem 3D e produção de pós-vídeo é extremamente forte. Diversas cenas de filmes que foram blockbusters no ano de 2012 foram feitas a partir dessa integração, como por…

..................................................................................... 30 MW_IqControl ........................................................................................................................................... 30 STOP ........................................................................................................................................... 31 QSTOP ................................................................................................

x = 0 . Therefore (4.80 m s )t − (0.360 m s )t 2 = 0 . The 2 3 2 3 only time after t = 0 when the car is at rest is t = 4.80 m s 2 0.360 m s 3 = 13.3 s 2.10: a) IV: The curve is horizontal; this corresponds to the time when she stops. b) I: This is the time when the curve is most nearly straight and tilted upward (indicating postive velocity). c) V: Here the curve is plainly straight, tilted downward (negative velocity). d) II: The curve has a postive slope that is…

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x = 0 . Therefore (4.80 m s )t − (0.360 m s )t 2 = 0 . The 2 3 2 3 only time after t = 0 when the car is at rest is t = 4.80 m s 2 0.360 m s 3 = 13.3 s 2.10: a) IV: The curve is horizontal; this corresponds to the time when she stops. b) I: This is the time when the curve is most nearly straight and tilted upward (indicating postive velocity). c) V: Here the curve is plainly straight, tilted downward (negative velocity). d) II: The curve has a postive slope that is…

x = 0 . Therefore (4.80 m s )t − (0.360 m s )t 2 = 0 . The 2 3 2 3 only time after t = 0 when the car is at rest is t = 4.80 m s 2 0.360 m s 3 = 13.3 s 2.10: a) IV: The curve is horizontal; this corresponds to the time when she stops. b) I: This is the time when the curve is most nearly straight and tilted upward (indicating postive velocity). c) V: Here the curve is plainly straight, tilted downward (negative velocity). d) II: The curve has a postive slope that is…

when v x = 0 . Therefore (4.80 m s )t − (0.360 m s )t 2 = 0 . The 2 only time after t = 0 when the car is at rest is t = 4.80 m s 2 0.360 m s 3 = 13.3 s 3 2.10: a) IV: The curve is horizontal; this corresponds to the time when she stops. b) I: This is the time when the curve is most nearly straight and tilted upward (indicating postive velocity). c) V: Here the curve is plainly straight, tilted downward (negative velocity). d) II: The curve has a postive slope that…

x = 0 . Therefore (4.80 m s )t − (0.360 m s )t 2 = 0 . The 2 3 2 3 only time after t = 0 when the car is at rest is t = 4.80 m s 2 0.360 m s 3 = 13.3 s 2.10: a) IV: The curve is horizontal; this corresponds to the time when she stops. b) I: This is the time when the curve is most nearly straight and tilted upward (indicating postive velocity). c) V: Here the curve is plainly straight, tilted downward (negative velocity). d) II: The curve has a postive slope that is…