Pinhole

economical means for corrosion control. Using the fluidized bed process, pretreated, preheated metal parts are dipped in an air-suspended bed of © 2002 by CRC Press LLC finely divided powder to produce coatings, which after baking are tough, pinhole free, and highly resistant to abrasion and chemical attack. Parts clad by this process are protected against corrosion both internally and externally. USES Complete anticorrosive systems are available with chlorinated polyether, and…

sense of security block all outbound and inbound UDP traffic (perhaps with the exception of DNS packets) and rely on SIP ALG to open the UDP pinholes (or translation) for the voice or video media streams. Teredo requires a specific NAT (or firewall pinhole) to be dynamically installed. And, this translation setting is not the default in IOS or ASA. On those devices, a static translation entry must be configured; otherwise, Teredo packets from Teredo relays do not go through the NAT. With…

ray shown is the only ray from the top of the object that reaches the film, so this ray passes through the top of the image. An inverted image is formed on the far side of the box, no matter how far this side is from the pinhole and no matter how far the object is from the pinhole. 20.0 cm s′ (b) s = 1.5 m . s′ = 20.0 cm . m = − = − = −0.133 . y′ = my = ( −0.133)(18 cm) = −2.4 cm . The image is 150 cm s 2.4 cm tall. EVALUATE: A defect of this camera is that not much light energy passes…

ray shown is the only ray from the top of the object that reaches the film, so this ray passes through the top of the image. An inverted image is formed on the far side of the box, no matter how far this side is from the pinhole and no matter how far the object is from the pinhole. 20.0 cm s′ (b) s = 1.5 m . s′ = 20.0 cm . m = − = − = −0.133 . y′ = my = ( −0.133)(18 cm) = −2.4 cm . The image is 150 cm s 2.4 cm tall. EVALUATE: A defect of this camera is that not much light energy passes…

ray shown is the only ray from the top of the object that reaches the film, so this ray passes through the top of the image. An inverted image is formed on the far side of the box, no matter how far this side is from the pinhole and no matter how far the object is from the pinhole. 20.0 cm s′ (b) s = 1.5 m . s′ = 20.0 cm . m = − = − = −0.133 . y′ = my = ( −0.133)(18 cm) = −2.4 cm . The image is 150 cm s 2.4 cm tall. EVALUATE: A defect of this camera is that not much light energy passes…

ray shown is the only ray from the top of the object that reaches the film, so this ray passes through the top of the image. An inverted image is formed on the far side of the box, no matter how far this side is from the pinhole and no matter how far the object is from the pinhole. 20.0 cm s′ (b) s = 1.5 m . s′ = 20.0 cm . m = − = − = −0.133 . y′ = my = ( −0.133)(18 cm) = −2.4 cm . The image is 150 cm s 2.4 cm tall. EVALUATE: A defect of this camera is that not much light…

ray shown is the only ray from the top of the object that reaches the film, so this ray passes through the top of the image. An inverted image is formed on the far side of the box, no matter how far this side is from the pinhole and no matter how far the object is from the pinhole. 20.0 cm s′ (b) s = 1.5 m . s′ = 20.0 cm . m = − = − = −0.133 . y′ = my = ( −0.133)(18 cm) = −2.4 cm . The image is 150 cm s 2.4 cm tall. EVALUATE: A defect of this camera is that not much light energy passes…

ray shown is the only ray from the top of the object that reaches the film, so this ray passes through the top of the image. An inverted image is formed on the far side of the box, no matter how far this side is from the pinhole and no matter how far the object is from the pinhole. 20.0 cm s′ (b) s = 1.5 m . s′ = 20.0 cm . m = − = − = −0.133 . y′ = my = ( −0.133)(18 cm) = −2.4 cm . The image is 150 cm s 2.4 cm tall. EVALUATE: A defect of this camera is that not much light energy passes…

ray shown is the only ray from the top of the object that reaches the film, so this ray passes through the top of the image. An inverted image is formed on the far side of the box, no matter how far this side is from the pinhole and no matter how far the object is from the pinhole. 20.0 cm s′ (b) s = 1.5 m . s′ = 20.0 cm . m = − = − = −0.133 . y′ = my = ( −0.133)(18 cm) = −2.4 cm . The image is 150 cm s 2.4 cm tall. EVALUATE: A defect of this camera is that not much light energy passes…

continuity and Bernoulli from 1 to 2: V1A1 = V2 A 2 , or V1 = 1 V2 ; 4 2 2 p1 V 1 pa V 2 + ≈ + ρ ρ 2 2 Introduce p1 − pa and substitute for V1 to obtain V 2 = 2 V2 = 5.61 2(28.65) , 1.94(1 − 1/16) ft s Ans. If we reduce section 2 to a pinhole, V2 will drop off slowly until V1 vanishes: Severely constricted section 2: V2 = 2(28.65) ft ≈ 5.43 s 1.94(1 − 0) Ans. 3.175 If the approach velocity is not too high, a hump in the bottom of a water channel causes a dip ∆h in…