memória de cálculo - bombas

RECALQUE
TRECHO 01:
Q=100 m^3/h
∅=6" = 0,154m
A= 〖π×D〗^2/4= 〖π×0,154〗^2/4=
A=0,0186m^2
v= Q/A= (100 m^3/h)/(0,0186m^2 )= v=(5356,3 m/h)/3600s v=1,79 m/s
Altura Geométrica=4mca
Pressão Requerida=4 Kgf/〖cm〗^2 =40mca

L_real= 25,18m
L_(equiv.)=314×0,154=49m
L_total=75m f=0,0180 R_e=(0,154×1,86)/0,00000103=
R_e=278097
CÁLCULO DA PERDA DE CARGA NO RECALQUE (TRECHO 01) h=0,0180×75/0,154×〖1,79〗^2/18,14 h=1,54m
〖AMT〗_total=40+4+1,54=
〖AMT〗_total=45,54mca

TRECHO 02:
Q=75 m^3/h
∅=4" = 0,102m
A= 〖π×D〗^2/4= 〖π×0,102〗^2/4=
A=0,00817m^2
v= Q/A= (75 m^3/h)/(0,00817m^2 )= v=(9179,92 m/h)/3600s v=2,54 m/s
L_real= 2,645m
L_(equiv.)=50×0,102=5,1m
L_total=7,75m f=0,0186 R_e=(0,102×2,54)/0,00000103=
R_e=251533,9
CÁLCULO DA PERDA DE CARGA NO RECALQUE (TRECHO 02) h=0,0186×7,75/0,102×〖2,54〗^2/18,14 h=0,502m
〖AMT〗_total=0,502mca

TRECHO 03:
Q=50 m^3/h
∅=4" = 0,102m
A= 〖π×D〗^2/4= 〖π×0,102〗^2/4=
A=0,00817m^2
v= Q/A= (50 m^3/h)/(0,00817m^2 )= v=(6119,9 m/h)/3600s v=1,69 m/s
L_real= 0,21m
L_(equiv.)=20×0,102=2,04m
L_total=2,25m f=0,0194 R_e=(0,102×1,69)/0,00000103=
R_e=167359,22
CÁLCULO DA PERDA DE CARGA NO RECALQUE (TRECHO 03) h=0,0194×2,25/0,102×〖1,69〗^2/18,14 h=0,0673m
〖AMT〗_total=0,0673mca

TRECHO 04:
Q=25 m^3/h
∅=4" = 0,102m
A= 〖π×D〗^2/4= 〖π×0,102〗^2/4=
A=0,00817m^2
v= Q/A= (25 m^3/h)/(0,00817m^2 )= v=(3059,97 m/h)/3600s v=0,85 m/s
L_real= 2,645m
L_(equiv.)=26×0,102=2,7m
L_total=5,35m f=0,0213 R_e=(0,102×0,85)/0,00000103=
R_e=84174,75
CÁLCULO DA PERDA DE CARGA NO RECALQUE (TRECHO 04) h=0,0213×5,35/0,102×〖0,85〗^2/18,14 h=0,045m
〖AMT〗_total=0,045mca

TRECHO 05:
Q=25 m^3/h
∅=2.1/2" = 0,06271m
A= 〖π×D〗^2/4= 〖π×0,06271〗^2/4=
A=0,00308m^2
v= Q/A= (25 m^3/h)/(0,00308m^2 )= v=(8116,8 m/h)/3600s v=2,25 m/s
L_real= 7,5m
L_(equiv.)=80×0,0308=4,96m
L_total=12,46m f=0,0211 R_e=(0,06271×2,25)/0,00000103=
R_e=136987,86
CÁLCULO DA PERDA DE CARGA NO RECALQUE (TRECHO