Estagio supervionado engenharia de produçao mecanica

EFh =0 H1 = 0 EM2=0
+v1.7-30x5-50x3=0
7.v1-150-150=0
7.v1=300
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V1=300/7=42,9 N
EFv=0
V1+v2-30-50-=0
42,9+v2-80=0
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V2=-37,1N
Mf:
0< x<2
Mf = v1.x p/x=0 mf=0 p/x =2 mf=v1.2
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mf= 85,8Nm
2<x<4
Mf= v1.x-30(x-2) p/x=2 mf=42.9.2-30(2-2) mf=85,8Nm p/ x=4 mf=42,9.4-30(4-2) mf=171,6-60=111,6Nm mf=v1.7-30.5-50.3 ------------------------------------------------- mf=42,9.7-300=0 4<x<7
Mf=v1.x-30(x-2)-50(x-4)
p/x=4 mf = 42,9.4-30.2-50.0=111,6Nm

Tensao total
& = N/A+mf/Wf
&= Mf/Wf
W°=PÍ.d³/32
W°=PÍ.10³/32 =3140
Wº= 3140/32 = 98,2mm³
&=111,6N.m/982N.m 1000mm/1m
&=1136,7N/mm²
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1,1Kgf/Cm²

Carga distribuída 0<x<4
EM2=0 EFV=0 Q=V1-qx p/x=4
V1.10-40.8=0 vi=v2-40=0 Q=32=10x Q=32.10.4=0
10.v1-320=0 32+v2-40=0 P/x=0 Q=8NM
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V1=32 v2=8N Q=32.10.0=0
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Mf:
0<x<4
Mf=v1.x-qx.x/2=v1x-q.x²/2 p/x=0 mf=v1.0-q.0²/2=0 p/x=4 mf=v1.4-q.4²/2=0
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mf=48Nm ou usar essa formula p/ mfv1.x-40(x-2)=Mf p/x=4 32.4-40.2=48