ED ESTUDOS DISCIPLINARES
A=36,87° B=53,13° C=3,375N
F12=0,015N F13=3,6N F23=3,375N
Fq1q3=3,6N
Fq2q3x=0,8X3,375 Fq2q3x=2,7N
Fr²=(Fq1q3+Fq2q3x)²+(Fq2q3y)²
Fr=6,62N
2-)(E)
Cos°=ca/hip Cos°=6,3/6,62
Cos°=0,92 Cos°=17,88°
3-)(A)
A=F/m
A=(((9000000000x0,001x0,001x0,0005)/(4,001)²/0,1)
A=2,8m/s²
4-)(B)
E=(9000000000x0,001x0,001)/4²
E=562,5N/C
5-)(C)
Emax para x= +/- (R/raiz de2)
X=+/-4/1,41 x=2,83m
6-)(B)
dE=(1/4PI£0).(dq/h²).cos° dE=(1/4PI£0).(dq/h²).(x/h) dE=(1/4PI£0).(dq.x/h³) dE=(1/4PI£0).(dq.x/r²+x²)^3/2 depois da integração:
E=(1/4PI£0).(x/x²)^3/2.Q
E=(1/4PI£0).(Q/x²)
7-)(A)
F=(1/4PI£0).[Q/(x-a).(x+a)]
F=9000000000x[0,000005/(9-5).(9+5)]
F=803,57 I N/C
8-)(E)
F=(1/4PI£0).[Q/(x-a).(x+a)]
F=9000000000x[0,00005/(85-5).(85+5)] F=6,25 I N/C
9-)(C)
V200=(9000000000x0,00005)/200 V400=225
V400=(9000000000x0,00005)/400 V400=112,5
V600=(9000000000x0,00005)/600 V400=75
V800=(9000000000x0,00005)/800 V400=56,25
Assim temos:
V200-V400=112,5m V400-V600=37,5m V600-V800=18,75m
10-)(A)
Trab=q.v Trab=0,002x(800-200) Trab=1,2J
11-)(A)
Eco=EPa 0,5.m.v0²=q.d d=(2mE)/(B²q) d=(2x0,000004x200)/(0,5²x0,032) d=0,2m
12-)(E)
F=qE+qvB F=qE F=0,032x200 F= -6,4jN
13-)(A)
(B-A)=0,3k (C-B)=-0,2j
Fab=I(B-A)xB Fab=4x0,3Kx0,5j Fab=-0,6i
Fbc=I(C-B)xB Fbc=4x-0,2Kx0,5j Fbc=0
14-)(B)
Trab=m.B Trab=(4x(0,2x0,3i))x0,5j Trab=0,12K
15-)(D)
Qgelo+Qfusao+Qequilibrio+Qagua=0
6x0,5x26+6x80+6T2+70T2-1050=0 76T2=492 T2=6,5°C
16-)(A)
Qgelo=mC(T2-T1) Qgelo=15x0,5x26 Qgelo=195cal
Qagua=mc(T2-T1) Qagua=76x1x-6,5 Qagua=494cal
Sobra: Q=494-195=299
Q=m.L 299=m.80 m=3,74g e Te=0°C
17-)(C)
Qab=nvc(tb-ta)+Tabab(área do trapézio)
Qab=nR1,5TB-nR1,5Ta+80 Qab=pb.vb.1,5-pa.va.1,5=80 Qab=8.10.1,5-8.2.1,5+80
Qab=176atm.L
18-)(B)
DeltaUab=Qab-Trabab Deltaab=176-80 Deltaab=96atm.L
19-)(C)
Trabab=[(2.6-12.2)/1-1,67]+nRTLn(va/vc)
Trabab=[(2.6-12.2)/1-1,67]+12.2Ln(2/6) Trabab=-8,45atm.L(x100) Trabab=-845J
20-)(A)
Ca- Isometrico
Qca=Pv.Ln(Va/Vc)