Ed 5°semestre eng prod
989 palavras
4 páginas
1∑FH=0 → HÁ=0
∑FV=0 →VA-VB -8+3=0
VA-VB=5 → VA=5+0,3 VA = 5,5 Tf
∑MA=0 -3*6+4VB+2*8=0
-18+4VB+16=0
VB=2/4 → VB=0,5 Tf
Resp. C
2
∑FH=0 → -HÁ+20=0 → HÁ=20tf
∑FV=0 → VA-VB-8-3=0
VA-VB=5 → VA=5+0,5 → VA = 5,5tf
∑MA=0 → -3*6+4*VB+8*2=0
-18+4VB+16=0
VB=2/4 → VB=0,5 Tf
Resp. A
3
∑FH=0 → +10+15=HB → HB=25KN
∑FV=0 → -40-10+VA+VB=0
VA+VB=50
∑MB=0 → +2VA-10*2+5-40*1+10*2=0
+2VA-20+5-40+20=0
VA=35/2 → VA=17,5KN
+15*2+10*4+40*1-2HB-2VB+5=0
30+40+40-50-2VB+5=0
VB=32,5KN
Resp. C
4
∑FH=0 → HA=10KN
∑FV=0 → VA+VB-10-20+10=0
VA-VB=20
VB+10-10-20=0
VB=20
Resp.D
5
RESUMIDO
VB=140,9/2,73
VB=51,6KN
RA=RB-52,5/0,5
RA=51,6-52,5/0,5
RA=-18KN
Resp.E
HB-77,5-51,6
HB=25,9KN
6
MS2=4*2-5*2-10+4
MS2=12KN.M
∑FH=0 → HB=5KN
∑FV=0 → -4+R → R=4KN
∑MA=0 → 4+5*2-4*1=M
M=10KN.M
MS1=+2(1,2)²/4=1,44KN.M
MS3=-4*2+5*2+10-4 = 8
MS4= -4*2+10=2KN.M
Resp. A
7
RA=17,5 ↑
HB=15+10 →HB=25KN
RA+RB=50
∑MA=0 → 15*2+10*4-25*2-RB*2+40*1+5=0
RB=32,5KN
RA=50-32,5
RA=17,5KN
Resp.C
8
CONFERIDO A RESPOSTA BATENDO RESULTADO ESSA FOI A QUE MAIS SE APROXIMOU
Resp.E
9
HB=0
RA+RB=40+10+10
RA+RB=60 → RA=60-30 → RA=30KN
∑MA=0 → -10*2+40*1-2RB+10*4=0
RB=60/2
RB=30KN
Resp. B
10
∑FH=0 → RA*COS60°-15+5*SEN36,87°
RA=15-5*SEN36,87°/COS60°
RA=24KN
HA=24*COS60° HA=12KN
∑MA=0 → 20+20*2-RB*8+4*4+3*4=0
RB=88/8
RB=11KN
∑FV=0 → 11-4-20+VA=0
VA=13KN
Resp.A
11
∑FH=0 → HA = 2KN
M=2*10 → M=20KN.M
Resp.C
12
HB=15+10 HB=25KN
RA+RB=50