Peps Ue

− 3) + 32 5 (z − 4) = 60x + (3.01)2 + (3.97)2 = f (1.98, 3.01, 3.97) ≈ 60(1.98) + 24 (3.01) 5 + 24 5y + 32 5z 32 (3.97) 5 − 120 − 120 = 38.656. ∂u dx ∂u dy ∂u dz du = + + = 2xy 3 (1 + 6p) + 3x2 y 2 (pep + ep ) + 4z 3 (p cos p + sin p) dp ∂x dp ∂y dp ∂z dp 37. By the Chain Rule, ∂z ∂x ∂z ∂y ∂z = + . When s = 1 and t = 2, x = g (1, 2) = 3 and y = h(1, 2) = 6, so ∂s ∂x ∂s ∂y ∂s ∂z ∂x ∂z ∂y ∂z ∂z = fx (3, 6)gs (1, 2)…